If the number of turns,area,and current through a coil are given by $N$,$A$,and $I$ respectively,then its magnetic moment will be:

The magnetic field at the centre of a current carrying circular coil of an area $A$ is $B$. The magnetic moment of the coil is (where $\mu_0$ is the permeability of free space).

The ratio of the magnetic field at the centre of a current-carrying circular coil to its magnetic moment is $\alpha$. If the current and radius both are doubled,then the new ratio will become:

$A$ spherical shell of radius $R$ carries a uniformly distributed charge $Q$ and is rotated about its diameter with angular speed $\omega$. Find its magnetic moment.

$A$ current-carrying circular loop is freely suspended by a long thread. The plane of the loop will point in the direction:

The dimensional formula for magnetic moment is: